Using the methods in this post, I would like to evaluate




Substituting, the expression to evaluate is

$ \frac{d r \sin\theta \cos \phi }{d\theta} \bigg|_{\theta^+}$.

From the product rule,

$ \frac{dx(\theta)}{d\theta} \bigg|_{\theta^+} = \sin\theta \frac{d r \cos \phi }{d\theta}\big|_{\theta^+} + r \cos \phi \frac{d \sin\theta }{d\theta}\big|_{\theta^+}$

Since $ r \cos \phi $ does not depend on $\theta$, $ r \cos \phi $ is a constant function with respect to $\theta$. From this post, it follows that

$\frac{d r \cos \phi }{d\theta} \bigg|_{\theta^+} = 0$, so

$ \frac{dx(\theta)}{d\theta} \bigg|_{\theta^+} = r \cos \phi \frac{d \sin\theta }{d\theta}\big|_{\theta^+} $

In this post, it was shown that

$ \frac{d \sin\theta}{d\theta} \bigg|_{\theta^+} = \cos\theta $.

In the current post, the independent variable is $\theta$ instead of $x$.


$ \boxed{ \frac{dx(\theta)}{d\theta} \bigg|_{\theta^+} = \cos\theta r \cos \phi   = z(r,\theta,\phi) \cos \phi  } $.

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