In this post, an expression for the electric field is derived.
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Proof of Gauss’ Theorem for a Rectangular Prism
Recall Gauss’ theorem, $ \int\int\int_V (\vec{\nabla} \cdot \vec{F}) dV = \int\int_{S} (\vec{F} \cdot \vec{e}_{n}) dS […]
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It turns out that deriving Gauss’ Law is easier said than done. There are several […]
Gauss’ Law, Part 1
In Derivation #3, the expression, $ \frac{\partial \beta(t)}{\partial t}$, was written. This is an expression […]