## How a Multivariable Function Changes with Respect to the Cartesian Coordinates

Suppose $F(x,y,z) \equiv f(x) g(y) h(z)$. This post shows how to calculate a partial derivative of a multivariable function $F(x,y,z)$ with respect to each Cartesian coordinates. The resulting expressions are in spherical coordinates. In previous…

For a functions $f(x)$, $g(y)$ and $h(z)$, the chain rule yields $\frac{\partial f(x)}{\partial \phi} = ( \frac{\partial f}{\partial x} ) ( \frac{\partial x}{\partial \phi} )$. $\frac{\partial g(y)}{\partial \phi} = (\frac{\partial g}{\partial y})… Read more ## How a Multivariable Function Changes with Respect to a Polar Coordinate For a functions$f(x)$,$g(y)$and$h(z)$, the chain rule yields$ \frac{\partial f(x)}{\partial \theta} = ( \frac{\partial f}{\partial x} ) ( \frac{\partial x}{\partial \theta} )$.$ \frac{\partial g(y)}{\partial \theta}  = (\frac{\partial g}{\partial y})…
First focus on the Cartesian coordinate $x$, which depends on the spherical coordinates $r,\theta,$ and $\phi$. For a function $f(x)$, the chain rule yields \$ \frac{\partial f(x)}{\partial r} = ( \frac{\partial f}{\partial x} )…